Conceptuellement, l’horizon est la limite de ce que l'on peut observer, du fait de sa propre position ou situation. Ce concept simple se décline en physique, philosophie, communication, et bien d'autres domaines :

This importance lessened with the development of the radio and the telegraph, but even today, when flying an aircraft under visual flight rules, a technique called attitude flying is used to control the aircraft, where the pilot uses the visual relationship between the aircraft's nose and the horizon to control the aircraft. A pilot can also retain his or her spatial orientation by referring to the horizon.

In many contexts, especially perspective drawing, the curvature of the Earth is disregarded and the horizon is considered the theoretical line to which points on any horizontal plane converge (when projected onto the picture plane) as their distance from the observer increases. For observers near sea level the difference between this geometrical horizon (which assumes a perfectly flat, infinite ground plane) and the true horizon (which assumes a spherical Earth surface) is imperceptible to the naked eye[dubious – discuss] (but for someone on a 1000-meter hill looking out to sea the true horizon will be about a degree below a horizontal line).

In astronomy the horizon is the horizontal plane through the eyes of the observer. It is the fundamental plane of the horizontal coordinate system, the locus of points that have an altitude of zero degrees. While similar in ways to the geometrical horizon, in this context a horizon may be considered to be a plane in space, rather than a line on a picture plane.

Distance to the horizon

One typically sees further along the Earth's curved surface than a simple geometric calculation allows for because of refraction error. If the ground, or water, surface is colder than the air above it, a cold, dense layer of air forms close to the surface, causing light to be refracted downward as it travels, and therefore, to some extent, to go around the curvature of the Earth. The reverse happens if the ground is hotter than the air above it, as often happens in deserts, producing mirages. As an approximate compensation for refraction, surveyors measuring distances longer than 300 feet subtract 14% from the calculated curvature error and ensure lines of sight are at least 5 feet from the ground, to reduce random errors created by refraction.

Typical desert horizon

However, ignoring the effect of atmospheric refraction, distance to the horizon from an observer close to the Earth's surface is about[5]

d ≈ 3.57 h , {\displaystyle d\approx 3.57{\sqrt {h}}\,,} d \approx 3.57\sqrt{h} \,,

where d is in kilometres and h is height above ground level in metres. The constant 3.57 has units of km/m½.

Examples:

For an observer standing on the ground with h = 1.70 metres (5 ft 7 in), the horizon is at a distance of 4.7 kilometres (2.9 mi).

For an observer standing on the ground with h = 2 metres (6 ft 7 in), the horizon is at a distance of 5 kilometres (3.1 mi).

For an observer standing on a hill or tower of 100 metres (330 ft) in height, the horizon is at a distance of 36 kilometres (22 mi).

For an observer standing at the top of the Burj Khalifa (828 metres (2,717 ft) in height), the horizon is at a distance of 103 kilometres (64 mi).

For an observer atop Mount Everest (8,848 metres (29,029 ft) in altitude), the horizon is at a distance of 336 kilometres (209 mi).

With d in miles (i.e. "land miles" of 5,280 feet (1,609.344 m)[5]) and h in feet,

d ≈ 1.5 h ≈ 1.22 h . {\displaystyle d\approx {\sqrt {1.5h}}\approx 1.22{\sqrt {h}}\,.} {\displaystyle d\approx {\sqrt {1.5h}}\approx 1.22{\sqrt {h}}\,.}

Where the constant 1.22 has units of mi/ft½. Examples, assuming no refraction:

For an observer on the ground with eye level at h = 5 ft 7 in (1.70 m), the horizon is at a distance of 2.9 miles (4.7 km).

For an observer standing on a hill or tower 100 feet (30 m) in height, the horizon is at a distance of 12.2 miles (19.6 km).

For an observer on the summit of Aconcagua (22,841 feet (6,962 m) in height), the sea-level horizon to the west is at a distance of 184 miles (296 km).

For a U-2 pilot, whilst flying at its service ceiling 70,000 feet (21,000 m), the horizon is at a distance of 324 miles (521 km)

Other planets

On terrestrial planets and other solid celestial bodies with negligible atmospheric effects, the distance to the horizon for a "standard observer" varies as the square root of the planet's radius. Thus, the horizon on Mercury is 62% as far away from the observer as it is on Earth, on Mars the figure is 73%, on the Moon the figure is 52%, on Mimas the figure is 18%, and so on.

Geometrical model

Geometrical basis for calculating the distance to the horizon, secant tangent theorem

Geometrical distance to the horizon, Pythagorean theorem

Three types of horizon

If the Earth is assumed to be a featureless sphere (rather than an oblate spheroid) with no atmospheric refraction, then the distance to the horizon can easily be calculated.[6]

The secant-tangent theorem states that

O C 2 = O A × O B . {\displaystyle \mathrm {OC} ^{2}=\mathrm {OA} \times \mathrm {OB} \,.} \mathrm{OC}^2 = \mathrm{OA} \times \mathrm{OB} \,.

Make the following substitutions:

d = OC = distance to the horizon

D = AB = diameter of the Earth

h = OB = height of the observer above sea level

D+h = OA = diameter of the Earth plus height of the observer above sea level

The formula now becomes

d 2 = h ( D + h ) {\displaystyle d^{2}=h(D+h)\,\!} d^2 = h(D+h)\,\!

or

d = h ( D + h ) = h ( 2 R + h ) , {\displaystyle d={\sqrt {h(D+h)}}={\sqrt {h(2R+h)}}\,,} d = \sqrt{h(D+h)} =\sqrt{h(2R+h)}\,,

where R is the radius of the Earth.

The equation can also be derived using the Pythagorean theorem. Since the line of sight is a tangent to the Earth, it is perpendicular to the radius at the horizon. This sets up a right triangle, with the sum of the radius and the height as the hypotenuse. With

d = distance to the horizon

h = height of the observer above sea level

R = radius of the Earth

referring to the second figure at the right leads to the following:

( R + h ) 2 = R 2 + d 2 {\displaystyle (R+h)^{2}=R^{2}+d^{2}\,\!} (R+h)^2 = R^2 + d^2 \,\!

R 2 + 2 R h + h 2 = R 2 + d 2 {\displaystyle R^{2}+2Rh+h^{2}=R^{2}+d^{2}\,\!} R^2 + 2Rh + h^2 = R^2 + d^2 \,\!

d = h ( 2 R + h ) . {\displaystyle d={\sqrt {h(2R+h)}}\,.} d = \sqrt{h(2R + h)} \,.

Another relationship involves the distance s along the curved surface of the Earth to the horizon; with γ in radians,

s = R γ ; {\displaystyle s=R\gamma \,;} s = R \gamma \,;

then

cos γ = cos s R = R R + h . {\displaystyle \cos \gamma =\cos {\frac {s}{R}}={\frac {R}{R+h}}\,.} \cos \gamma = \cos\frac{s}{R}=\frac{R}{R+h}\,.

Solving for s gives

s = R cos − 1 R R + h . {\displaystyle s=R\cos ^{-1}{\frac {R}{R+h}}\,.} s=R\cos^{-1}\frac{R}{R+h} \,.

The distance s can also be expressed in terms of the line-of-sight distance d; from the second figure at the right,

tan γ = d R ; {\displaystyle \tan \gamma ={\frac {d}{R}}\,;} \tan \gamma = \frac {d} {R} \,;

substituting for γ and rearranging gives

s = R tan − 1 d R . {\displaystyle s=R\tan ^{-1}{\frac {d}{R}}\,.} s=R\tan^{-1}\frac{d}{R} \,.

The distances d and s are nearly the same when the height of the object is negligible compared to the radius (that is, h ≪ R).

Approximate geometrical formulas

Graphs of distances to the true horizon on Earth for a given height h. s is along the surface of the Earth, d is the straight line distance, and ~d is the approximate straight line distance assuming h << the radius of the Earth, 6371 km. In the SVG image, hover over a graph to highlight it.

If the observer is close to the surface of the earth, then it is valid to disregard h in the term (2R + h), and the formula becomes-

d = 2 R h . {\displaystyle d={\sqrt {2Rh}}\,.} d = \sqrt{2Rh} \,.

Using kilometres for d and R, and metres for h, and taking the radius of the Earth as 6371 km, the distance to the horizon is

d ≈ 2 ⋅ 6371 ⋅ h / 1000 ≈ 3.570 h , {\displaystyle d\approx {\sqrt {2\cdot 6371\cdot {h/1000}}}\approx 3.570{\sqrt {h}}\,,} d \approx \sqrt{2\cdot6371\cdot{h/1000}} \approx 3.570\sqrt{h} \,,.

Using imperial units, with d and R in statute miles (as commonly used on land), and h in feet, the distance to the horizon is

d ≈ 2 ⋅ 3963 ⋅ h / 5280 ≈ 1.5 h ≈ 1.22 h {\displaystyle d\approx {\sqrt {2\cdot 3963\cdot {h/5280}}}\approx {\sqrt {1.5h}}\approx 1.22{\sqrt {h}}} {\displaystyle d\approx {\sqrt {2\cdot 3963\cdot {h/5280}}}\approx {\sqrt {1.5h}}\approx 1.22{\sqrt {h}}}.

If d is in nautical miles, and h in feet, the constant factor is about 1.06, which is close enough to 1 that it is often ignored, giving:

d ≈ h {\displaystyle d\approx {\sqrt {h}}} d \approx \sqrt h

These formulas may be used when h is much smaller than the radius of the Earth (6371 km or 3959 mi), including all views from any mountaintops, airplanes, or high-altitude balloons. With the constants as given, both the metric and imperial formulas are precise to within 1% (see the next section for how to obtain greater precision).

Exact formula for a spherical Earth

If h is significant with respect to R, as with most satellites, then the approximation made previously is no longer valid, and the exact formula is required:

d = 2 R h + h 2 , {\displaystyle d={\sqrt {2Rh+h^{2}}}\,,} d = \sqrt{2Rh + h^2} \,,

where R is the radius of the Earth (R and h must be in the same units). For example, if a satellite is at a height of 2000 km, the distance to the horizon is 5,430 kilometres (3,370 mi); neglecting the second term in parentheses would give a distance of 5,048 kilometres (3,137 mi), a 7% error.

Objects above the horizon

Geometrical horizon distance

To compute the greatest distance at which an observer can see the top of an object above the horizon, compute the distance to the horizon for a hypothetical observer on top of that object, and add it to the real observer's distance to the horizon. For example, for an observer with a height of 1.70 m standing on the ground, the horizon is 4.65 km away. For a tower with a height of 100 m, the horizon distance is 35.7 km. Thus an observer on a beach can see the top of the tower as long as it is not more than 40.35 km away. Conversely, if an observer on a boat (h = 1.7 m) can just see the tops of trees on a nearby shore (h = 10 m), the trees are probably about 16 km away.

Referring to the figure at the right, the top of the lighthouse will be visible to a lookout in a crow's nest at the top of a mast of the boat if

D B L < 3.57 ( h B + h L ) , {\displaystyle D_{\mathrm {BL} }<3.57\,({\sqrt {h_{\mathrm {B} }}}+{\sqrt {h_{\mathrm {L} }}})\,,} D_\mathrm{BL} < 3.57\,(\sqrt{h_\mathrm{B}} + \sqrt{h_\mathrm{L}}) \,,

where DBL is in kilometres and hB and hL are in metres.

A view across a 20-km-wide bay in the coast of Spain. Note the curvature of the Earth hiding the base of the buildings on the far shore.

As another example, suppose an observer, whose eyes are two metres above the level ground, uses binoculars to look at a distant building which he knows to consist of thirty storeys, each 3.5 metres high. He counts the storeys he can see, and finds there are only ten. So twenty storeys or 70 metres of the building are hidden from him by the curvature of the Earth. From this, he can calculate his distance from the building:

D ≈ 3.57 ( 2 + 70 ) {\displaystyle D\approx 3.57({\sqrt {2}}+{\sqrt {70}})} D \approx 3.57(\sqrt{2}+\sqrt{70})

which comes to about 35 kilometres.

It is similarly possible to calculate how much of a distant object is visible above the horizon. Suppose an observer's eye is 10 metres above sea level, and he is watching a ship that is 20 km away. His horizon is:

3.57 10 {\displaystyle 3.57{\sqrt {10}}} 3.57 \sqrt{10}

kilometres from him, which comes to about 11.3 kilometres away. The ship is a further 8.7 km away. The height of a point on the ship that is just visible to the observer is given by:

h ≈ ( 8.7 3.57 ) 2 {\displaystyle h\approx \left({\frac {8.7}{3.57}}\right)^{2}} h\approx\left(\frac{8.7}{3.57}\right)^2

which comes to almost exactly six metres. The observer can therefore see that part of the ship that is more than six metres above the level of the water. The part of the ship that is below this height is hidden from him by the curvature of the Earth. In this situation, the ship is said to be hull-down.

Effect of atmospheric refraction

If the Earth were an airless world like the Moon, the above calculations would be accurate. However, Earth has an atmosphere of air, whose density and refractive index vary considerably depending on the temperature and pressure. This makes the air refract light to varying extents, affecting the appearance of the horizon. Usually, the density of the air just above the surface of the Earth is greater than its density at greater altitudes. This makes its refractive index greater near the surface than at higher altitudes, which causes light that is travelling roughly horizontally to be refracted downward.[7] This makes the actual distance to the horizon greater than the distance calculated with geometrical formulas. With standard atmospheric conditions, the difference is about 8%.[citation needed] This changes the factor of 3.57, in the metric formulas used above, to about 3.86. This correction can be, and often is, applied as a fairly good approximation when conditions are close to standard. When conditions are unusual, this approximation fails. Refraction is strongly affected by temperature gradients, which can vary considerably from day to day, especially over water. In extreme cases, usually in springtime, when warm air overlies cold water, refraction can allow light to follow the Earth's surface for hundreds of kilometres. Opposite conditions occur, for example, in deserts, where the surface is very hot, so hot, low-density air is below cooler air. This causes light to be refracted upward, causing mirage effects that make the concept of the horizon somewhat meaningless. Calculated values for the effects of refraction under unusual conditions are therefore only approximate.[5] Nevertheless, attempts have been made to calculate them more accurately than the simple approximation described above.

Outside the visual wavelength range, refraction will be different. For radar (e.g. for wavelengths 300 to 3 mm i.e. frequencies between 1 and 100 GHz) the radius of the Earth may be multiplied by 4/3 to obtain an effective radius giving a factor of 4.12 in the metric formula i.e. the radar horizon will be 15% beyond the geometrical horizon or 7% beyond the visual. The 4/3 factor is not exact, as in the visual case the refraction depends on atmospheric conditions.

Integration method—Sweer

If the density profile of the atmosphere is known, the distance d to the horizon is given by[8]

d = R E ( ψ + δ ) , {\displaystyle d={{R}_{\text{E}}}\left(\psi +\delta \right)\,,} d={{R}_{\text{E}}}\left( \psi +\delta \right) \,,

where RE is the radius of the Earth, ψ is the dip of the horizon and δ is the refraction of the horizon. The dip is determined fairly simply from

cos ψ = R E μ 0 ( R E + h ) μ , {\displaystyle \cos \psi ={\frac {{R}_{\text{E}}{\mu }_{0}}{\left({{R}_{\text{E}}}+h\right)\mu }}\,,} \cos \psi = \frac{{R}_{\text{E}}{\mu}_{0}}{\left( {{R}_{\text{E}}}+h \right)\mu } \,,

where h is the observer's height above the Earth, μ is the index of refraction of air at the observer's height, and μ0 is the index of refraction of air at Earth's surface.

The refraction must be found by integration of

δ = − ∫ 0 h tan ϕ d μ μ , {\displaystyle \delta =-\int _{0}^{h}{\tan \phi {\frac {{\text{d}}\mu }{\mu }}}\,,} \delta =-\int_{0}^{h}{\tan \phi \frac{\text{d}\mu }{\mu }} \,,

where ϕ {\displaystyle \phi \,\!} \phi \,\! is the angle between the ray and a line through the center of the Earth. The angles ψ and ϕ {\displaystyle \phi \,\!} \phi \,\! are related by

ϕ = 90 ∘ − ψ . {\displaystyle \phi =90{}^{\circ }-\psi \,.} \phi =90{}^\circ -\psi \,.

Simple method—Young

A much simpler approach, which produces essentially the same results as the first-order approximation described above, uses the geometrical model but uses a radius R′ = 7/6 RE. The distance to the horizon is then[5]

d = 2 R ′ h . {\displaystyle d={\sqrt {2R^{\prime }h}}\,.} d=\sqrt{2 R^\prime h} \,.

Taking the radius of the Earth as 6371 km, with d in km and h in m,

d ≈ 3.86 h ; {\displaystyle d\approx 3.86{\sqrt {h}}\,;} d \approx 3.86 \sqrt{h} \,;

with d in mi and h in ft,

d ≈ 1.32 h . {\displaystyle d\approx 1.32{\sqrt {h}}\,.} d \approx 1.32 \sqrt{h} \,.

Results from Young's method are quite close to those from Sweer's method, and are sufficiently accurate for many purposes.

Curvature of the horizon

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The curvature of the horizon is easily seen in this photograph, taken from a space shuttle at an altitude of 226 km in 2008.

From a point above the surface the horizon appears slightly bent (it is a circle). There is a basic geometrical relationship between this visual curvature κ {\displaystyle \kappa } \kappa , the altitude h {\displaystyle h} h, and the Earth's radius R {\displaystyle R} R, . It is

κ = ( 1 + h R ) 2 − 1 . {\displaystyle \kappa ={\sqrt {\left(1+{\frac {h}{R}}\right)^{2}-1}}\ .} \kappa=\sqrt{\left(1+\frac{h}{R}\right)^2-1}\ .

The curvature is the reciprocal of the curvature angular radius in radians. A curvature of 1 appears as a circle of an angular radius of 57.3° corresponding to an altitude of approximately 2640 km above the Earth's surface. At an altitude of 10 km (33,000 ft, the typical cruising altitude of an airliner) the mathematical curvature of the horizon is about 0.056, the same curvature of the rim of circle with a radius of 10 m that is viewed from 56 cm directly above the center of the circle. However, the apparent curvature is less than that due to refraction of light in the atmosphere and because the horizon is often masked by high cloud layers that reduce the altitude above the visual surface.

Vanishing points

Two points on the horizon are at the intersections of the lines extending the segments representing the edges of the building in the foreground. The horizon line coincides here with the line at the top of the doors and windows.

Main article: Vanishing point

The horizon is a key feature of the picture plane in the science of graphical perspective. Assuming the picture plane stands vertical to ground, and P is the perpendicular projection of the eye point O on the picture plane, the horizon is defined as the horizontal line through P. The point P is the vanishing point of lines perpendicular to the picture. If S is another point on the horizon, then it is the vanishing point for all lines parallel to OS. But Brook Taylor (1719) indicated that the horizon plane determined by O and the horizon was like any other plane:

The term of Horizontal Line, for instance, is apt to confine the Notions of a Learner to the Plane of the Horizon, and to make him imagine, that that Plane enjoys some particular Privileges, which make the Figures in it more easy and more convenient to be described, by the means of that Horizontal Line, than the Figures in any other plane;…But in this Book I make no difference between the Plane of the Horizon, and any other Plane whatsoever...[9][10]

The peculiar geometry of perspective where parallel lines converge in the distance, stimulated the development of projective geometry which posits a point at infinity where parallel lines meet. In her book Geometry of an Art (2007), Kirsti Andersen described the evolution of perspective drawing and science up to 1800, noting that vanishing points need not be on the horizon. In a chapter titled "Horizon", John Stillwell recounted how projective geometry has led to incidence geometry, the modern abstract study of line intersection. Stillwell also ventured into foundations of mathematics in a section titled "What are the Laws of Algebra ?" The "algebra of points", originally given by Karl von Staudt deriving the axioms of a field was deconstructed in the twentieth century, yielding a wide variety of mathematical possibilities. Stillwell states

This discovery from 100 years ago seems capable of turning mathematics upside down, though it has not yet been fully absorbed by the mathematical community. Not only does it defy the trend of turning geometry into algebra, it suggests that both geometry and algebra have a simpler foundation than previously thought.[11]

See also

Aerial landscape art

Atmospheric refraction

Dawn

Dusk

Horizontal and vertical

Landscape

Landscape art

Limb[disambiguation needed]

Limb darkening

Lunar limb

Sextant

References

"Offing". Webster's Third New International Dictionary (Unabridged ed.). Pronounced, "Hor-I-zon".

Liddell, Henry George & Scott, Robert. "ὁρίζων". A Greek-English Lexicon. Perseus Digital Library. Archived from the original on June 5, 2011. Retrieved April 19, 2011.

Liddell, Henry George & Scott, Robert. "ὁρίζω". A Greek-English Lexicon. Perseus Digital Library. Archived from the original on June 5, 2011. Retrieved April 19, 2011.

Liddell, Henry George & Scott, Robert. "ὅρος". A Greek-English Lexicon. Perseus Digital Library. Archived from the original on June 5, 2011. Retrieved April 19, 2011.

Young, Andrew T. "Distance to the Horizon". Green Flash website (Sections: Astronomical Refraction, Horizon Grouping). San Diego State University Department of Astronomy. Archived from the original on October 18, 2003. Retrieved April 16, 2011.

Plait, Phil (15 January 2009). "How far away is the horizon?". Discover. Bad Astronomy. Kalmbach Publishing Co. Archived from the original on 29 March 2017. Retrieved 2017-03-28.

Proctor, Richard Anthony; Ranyard, Arthur Cowper (1892). Old and New Astronomy. Longmans, Green and Company. p. 73. Archived from the original on 2017-03-29.

Sweer, John (1938). "The Path of a Ray of Light Tangent to the Surface of the Earth". Journal of the Optical Society of America. 28: 327–329. doi:10.1364/JOSA.28.000327. (Subscription required (help)).

Taylor, Brook. New Principles of Perspective. p. 1719.

Anderson, Kirsti (1991). "Brook Taylor's Work on Linear Perspective". Springer. p. 151. ISBN 0-387-97486-5.

Stillwell, John (2006). "Yearning for the Impossible". Horizon. A K Peters, Ltd. pp. 47–76. ISBN 1-56881-254-X.

Further reading

Young, Andrew T. "Dip of the Horizon". Green Flash website (Sections: Astronomical Refraction, Horizon Grouping). San Diego State University Department of Astronomy. Retrieved April 16, 2011.

Sciences et techniques

Géologie

Un horizon en pédologie est une couche du sol, homogène et parallèle à la surface.

Informatique

Horizon, un logiciel SIGB de la société SirsiDynix ;

New Horizon Interactive, société de logiciels ;

Horizon, un jeu d'arcade.

Physique

L’horizon est un cercle centré sur l’observateur entre le ciel et la Terre, tenant compte de la courbure de cette dernière ;

L’horizon des particules est la limite de la région de l'espace-temps susceptible d'influencer un point donné ;

En particulier, l’horizon cosmologique est la limite de l'univers visible depuis la Terre, est, sous certaines conditions, un horizon des particules ;

L’horizon des évènements est la limite de la région de l'espace-temps influençable depuis un point donné ;

En particulier, l’horizon d'un trou noir est la frontière entre un trou noir et le reste de l'univers, est un horizon des événements.

Sciences humaines

Un horizon en philosophie, un concept à rapprocher de l'aveuglement ;

L’horizon, la classification chronologique des périodes précolombiennes dans les Andes centrales (Bolivie et Pérou).

Technique

L’horizon-radar est la distance maximale que peut atteindre le faisceau radar à un angle de site nul.

Arts et culture

Cinéma / télévision

L'Horizon est un film de Lev Koulechov (1932) ;

Horizons sans fin, film de Jean Dréville (1953) ;

L'Horizon est un film de Jacques Rouffio (1967) ;

Event Horizon, le vaisseau de l'au-delà est un film américain de Paul W. S. Anderson (1997) ;

Horizon est une émission de télévision diffusée par la BBC.

Jeu vidéo

Horizon, shoot 'em up d'Irem sorti en 1985

Horizon, jeu 4X de L3O Interactive sorti en 2014

Horizon Zero Dawn, action-RPG de Guerrilla Games à paraître en 2016

Musique

Horizon est un single de The Cinematic Orchestra sorti en 2002 ;

L'Horizon est un album de musique de Dominique A sorti en 2006 ;

Horizons est un album de Détroit sorti en 2013 ;

Horizons est une chanson du groupe Genesis sorti en 1972.

Horizon est une chanson de l'album Private Collection de Jon & Vangelis sortie en 1983

Littérature

Les Horizons vaincus, un livre de l'alpiniste italien Reinhold Messner relatant son ascension en solitaire et sans oxygène de l'Everest ;

Horizon est le quatrième et dernier tome de la tétralogie de fantasy Le Couteau du partage de Lois McMaster Bujold ;

L'Horizon est un roman de Patrick Modiano paru en 2010.

Médias

Presse

Horizons, un quotidien algérien en langue française ;

Horizons, le magazine de la recherche du Fonds national suisse de la recherche scientifique (FNS) et des Académies suisses des sciences (également édité en allemand sous le titre Horizonte).

Radio

Horizon, une radio locale française de catégorie B, fondée en 1985 et diffusant ses programmes sur une partie de la région Hauts-de-France ;

Horizon, une station de radio locale implantée en Seine-Maritime, fondée en 1982.

Produits, services et organisations

Air Horizons, une compagnie aérienne française ;

Horizons, une ancienne attraction du parc Epcot à Walt Disney World Resort ;

La Simca-Talbot Horizon, une voiture des marques Simca et Talbot ;

Classe Horizon, frégates franco-italiennes ;

Horizon, un navire de croisière construit en 1990 ;

Réseau de bus Horizon, bus de l'agglomération de Châteauroux ;

New Horizons, une sonde spatiale de la NASA pour l'étude de Pluton et de la ceinture de Kuiper.

Voir aussi

Sur les autres projets Wikimedia :

Horizon, sur Wikimedia Commons horizon, sur le Wiktionnaire Horizon, sur Wikiquote

Horizons lointains Ce lien renvoie vers une page d'homonymie

Les Horizons perdus Ce lien renvoie vers une page d'homonymie

Nouveaux Horizons Ce lien renvoie vers une page d'homonymie

Title Goonhilly

Released 22/02/2018 10:39 am

Copyright GES - Goonhilly Earth Station Ltd.

Description

Goonhilly Earth Station, a commercial tracking station in Cornwall, UK, will be upgraded to provide Europe’s first deep-space services on a commercial basis.

Under the project, the station’s GHY-6 antenna (seen here), built in 1985 and featuring a 32 m-diameter dish, will be upgraded to provide high bit-rate data links for missions far from Earth – typically exceeding 2 million km.

These include not only missions to our somewhat closer Moon, but also to the asteroids and planetary destinations such as Mars.

More information

Major European Space Agency Project at Goonhilly

ESA ground station network

Id 390564

http://www.esa.int/spaceinimages/Images/2018/02/Goonhilly2MOSAÏQUE ET SENTIMENTS

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